Deep Computerized Adaptive Testing

Jiguang Li et al.

Psychometrika2026https://doi.org/10.1017/psy.2026.10106article
AJG 3
Weight
0.50

What the paper says

Computerized adaptive tests (CATs) play a crucial role in educational assessment and diagnostic screening in behavioral health.Unlike traditional linear tests that administer a fixed set of pre-assembled items, CATs adaptively tailor the test to an examinee's latent trait level based on their previous responses.We introduce a novel CAT system that builds on recent advances in Bayesian multivariate IRT.Our approach leverages direct sampling from the latent factor posterior distributions, significantly accelerating existing information-theoretic item selection methods by eliminating the need for computationally intensive Markov Chain Monte Carlo (MCMC) simulations.To address the potential suboptimality of one-step-ahead item selection rules, we also develop a double deep Q-learning algorithm that efficiently learns an optimal item-selection policy offline using a calibrated item bank.Through simulation and real-data studies, we demonstrate that our approach not only accelerates existing item selection methods but also highlights the potential of reinforcement learning in CATs.Notably, our Q-learning-based strategy consistently achieves the fastest posterior variance reduction, leading to earlier test termination.These results demonstrate the promise of combining exact posterior sampling with reinforcement learning to deliver scalable, high-precision CATs.

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https://doi.org/https://doi.org/10.1017/psy.2026.10106

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@article{jiguang2026,
  title        = {{Deep Computerized Adaptive Testing}},
  author       = {Jiguang Li et al.},
  journal      = {Psychometrika},
  year         = {2026},
  doi          = {https://doi.org/https://doi.org/10.1017/psy.2026.10106},
}

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Evidence weight

0.50

Balanced mode · F 0.40 / M 0.15 / V 0.05 / R 0.40

F · citation impact0.50 × 0.4 = 0.20
M · momentum0.50 × 0.15 = 0.07
V · venue signal0.50 × 0.05 = 0.03
R · text relevance †0.50 × 0.4 = 0.20

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